Respuesta :
Answer : The volume of nitrogen gas equal to [tex]3.42\times 10^{22}[/tex] molecules of this substance is, 1.27 liters.
Explanation :
First we have to calculate the moles of nitrogen gas.
As, [tex]6.022\times 10^{23}[/tex] molecules present in 1 mole of nitrogen gas
So, [tex]3.42\times 10^{22}[/tex] molecules present in [tex]\frac{3.42\times 10^{22}}{6.022\times 10^{23}}=0.0568[/tex]mole of nitrogen gas
Now we have to calculate the volume of nitrogen gas.
As we know that, 1 mole of substance occupies 22.4 L volume of gas at STP.
As, 1 mole of nitrogen gas occupies 22.4 L volume of nitrogen gas
So, 0.0568 mole of nitrogen gas occupies [tex]0.0568\times 22.4=1.27L[/tex] volume of nitrogen gas
Therefore, the volume of nitrogen gas equal to [tex]3.42\times 10^{22}[/tex] molecules of this substance is, 1.27 liters.
