Respuesta :
Answer: p-value = 0.1085 and we will not reject the null hypothesis.
Step-by-step explanation:
Since we have given that
Hypothesis are :
[tex]H_0:p=0.3\\\\H_1:p>0.3[/tex]
Here, n = 200
x = 68
So, [tex]\hat{p}=\dfrac{68}{200}=0.34[/tex]
So, the test statistic value would be :
[tex]z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.34-0.3}{\sqrt{\dfrac{0.3\times 0.7}{200}}}\\\\z=\dfrac{0.04}{0.0324}\\\\z=1.234[/tex]
So, the value of statistic value is 1.234.
And the p-value = 0.1085 at 5% level of significance.
So, 0.1085 < 1.234,
So, we will not reject the null hypothesis.
Hence, p-value = 0.1085 and we will not reject the null hypothesis.
The value of p is 0.34.
The value of the static hypothesis is 1.23.
The statistical division when the alpha = 0.05 is 0.1085.
The value of the statical hypothesis is greater than the null hypothesis and the value of p so the value of not rejects the null hypothesis.
Given that,
A movie production company is releasing a movie with the hopes of many viewers returning to see the movie in the theater for a 2nd time.
The target is to have 30 million viewers and they want more than 30% of the viewers to return to see the movie again.
They show the movie to a test audience of 200 people.
Of the test audience, 68 people said they would see it again.
We have to determine,
A. Explain what the p-value is?
B. What is the p-value for the test statistic.
C. What is the statistical division when the alpha = 0.05
D. Explain the managerial conclusion for this situation.
According to the question,
1. The null hypothesis is,
[tex]\rm H_0; p =3\\\\H_1 ; = p>0.3[/tex]
They show the movie to a test audience of 200 people.
n = 200
And of the test audience, 68 people said they would see it again.
x = 68
Then the value of p is,
[tex]=\dfrac{68}{200}\\\\=0.34[/tex]
The value of p is 0.34.
2. The test hypothesis is,
[tex]\rm z =\dfrac{p-p_1}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\ z =\dfrac{0.34-0.3}{\sqrt{\dfrac{0.3(1-0.3)}{200}}}\\\\ z =\dfrac{0.04}{\sqrt{\dfrac{0.3\times 0.7}{200}}}\\\\ z =\dfrac{0.04}{\sqrt{\dfrac{0.21}{200}}}\\\\ z =\dfrac{0.04}{0.0324}\\\\z = 1.234[/tex]
The value of the static hypothesis is 1.234.
3. The p-value = 0.1085 at 5% level of significance.
So, 0.1085 < 1.234,
Here the null hypothesis is not rejected.
Hence, p-value = 0.1085, and we will not reject the null hypothesis.
4. The value of the statical hypothesis is greater than the null hypothesis and the value of p so the value of not rejects the null hypothesis.
For more details click the link given below.
https://brainly.com/question/18666111
