Respuesta :

konrad509
[tex]\cot x=\dfrac{\cos x}{\sin x}\\ \cos x=\cot x \sin x\\ \cos x=0.42\cdot0.92=0.3864[/tex]
dalendrk
[tex]\cot\alpha=\dfrac{\cos\alpha}{\sin\alpha}\\\\\cot x=0.42;\ \sin x=0.92;\ \cos x=?\\\\subtitute\\\\\dfrac{\cos x}{0.92}=0.42\ \ \ |multiply\ both\ sides\ by\ 0.92\\\\\boxed{\cos x=0.3864\approx0.39}[/tex]