Please can someone help me with this question

Answer:
r = -[tex]\frac{6a}{1-5m^2}[/tex]
Step-by-step explanation:
Rewrite the equation as [tex]\sqrt{x} 6a+r/5r[/tex] = m
Remove the radical on the left side of the equation by squaring both sides of the equation.
([tex]\sqrt{\frac{6a+r}{5r} )^{2}[/tex] = m^2
Then, you simplify each of the equation.
Rewrite: ([tex]\sqrt{\frac{6a+r}{5r} )^{2}[/tex] as [tex]\frac{6a+r}{5r} = m^{2}[/tex]
Remove any parentheses if needed.
Solve for r.
Multiply each term by r and simplify."
Multiply both sides of the equation by 5.
6a+r= m^2r⋅(5)
Remove parentheses.
Move 5 to the left of (m ^2) r
6a+r=5m^2)r
Subtract 5m^2)r from both sides of the equation.
6a+r-5m^2)r=0
Subtract 6a from both sides of the equation.
r-5m^2)r=-6a
Factor r out of r-5m^2)r
r(1-5m^2)=-6a
Divide each term by 1-5m^2 and simplify.
r = - [tex]\frac{6a}{1-5m^2}[/tex]
There you go, hope this helps!