The probability that a student plays football or baseball is 28/33.
Step-by-step explanation:
From the Venn diagram, it can be determined that
The total number of students = 26+3+9+6+5+7+10 = 66 students.
- The No.of of students play football alone = 26
- The No.of students play baseball alone = 9
- The No.of students play basketball alone = 10
The Probability that a student plays football or baseball = No.of students who knows to play either football or baseball / Total no.of students.
- The No.of students who play both football and baseball = 3
- The No.of students who play both football and basketball = 10
- The No.of students who play both baseball and basketball = 7
- The No.of students play all the games = 5
Now, to find the no.of students who plays football or baseball :
⇒ Total students - (students who plays basket ball alone)
This is because, all the other category students knows to play either football or baseball.
⇒ 66 - 10
⇒ 56 students.
The no.of students who plays football or baseball is 56 students.
Therefore, P(student plays football or baseball) = 56/66 ⇒ 28/33
The Probability is 28/33 which is option D).
