Answer:
The angular deflection of wavelength 656 nm in the 1st order is 20.31⁰
Explanation:
Angular deflection of wavelength 656 nm in the first order
The angle of deflection could be gotten using the relation:
[tex]sin (\theta_{n} ) = \frac{n \lambda}{d}[/tex]
Where λ = wavelength of the light emitted from the hot gas
d = distance between two slits
n = order of deflection
Since we are looking for the angular deflection in the first order, n= 1
d = 1/5300
d = 1.89 * 10⁻⁴ cm
d = 1.89 * 10⁻⁴ * 10⁻² m = 1.89 * 10⁻⁶m
d = 1.89 μm
[tex]sin (\theta_{1} ) = \frac{1 * 656 * 10^{-9} }{1.89 * 10^{-6} }[/tex]
[tex]sin (\theta_{1}) = 0.347\\\theta_{1} = sin^{-1} 0.347\\\theta_{1} =20.31^{0}[/tex]
