contestada

If a pitcher throws a 120 m/s fastball how much force does he need to apply if he is in contact with the ball for 1.5 seconds

Respuesta :

Answer:

Force on the fast ball is given as

[tex]F = m(80)[/tex]

here m = mass of the ball

Explanation:

As we know that initially fast ball is moving with speed 120 m/s

now after force applied to the ball it comes to rest

So final speed of the ball is ZERO

now time interval of applied force is

t = 1.5 s

now we have

[tex]a = \frac{v_f - v_i}{t}[/tex]

[tex]a = \frac{0 - 120}{1.5}[/tex]

[tex]a = -80 m/s^2[/tex]

Now as per Newton's II law we know

[tex]F = ma[/tex]

[tex]F = m(80)[/tex]

here m = mass of the ball

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