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help me, please!
A biologist is researching a newly-discovered species of bacteria. At time t = 0hours, he puts one hundred bacteria into what he has determined to be a favorable growth medium. Six hours later, he measures 600 bacteria. Assuming exponential growth, shown by the equation A = Pekt,what is the growth constant "k" for the bacteria? (Round k to two decimal places.)

Respuesta :

Match the function with the graph

Answer:

0.30

Step-by-step explanation:

1. P (starting population) = 100

2. t (time) = 6

3. A (population at a given time) = 600 (in our case, this is the population at 6 hours)

4. [tex]600 = 100e^{6k} --> 6 = e^{6k} --> ln(6) = 6k --> ln(6)/6 = k --> 0.2986265782 = k[/tex]

5. Therefore, 0.30 = k (with rounding)

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