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The flywheel of a steam engine runs with a constant angular speed of 405 rev/min (in the counterclockwise direction). When steam is shut off, the friction of the bearings stops the wheel in 1.9 h.
What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown?

Respuesta :

Khoso123

Answer:

[tex]\alpha =-3.552rev/min^{2}[/tex]

Explanation:

Given data

The angular velocity of flywheel ω₀=405 rev/min

The wheel stops after 1.9 hours

To find

Constant angular acceleration

Solution

Using the equation angular motion to find constant angular acceleration of the flywheel during slow down

[tex]w=w_{o}+\alpha t[/tex]

Substitute the given values

So

[tex]0=405rev/min+\alpha (1.9*60min)\\\alpha =\frac{-405}{1.9*60} \\\alpha =-3.552rev/min^{2}[/tex]  

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