Labb5ittlessellC
contestada

HELP ME PLEASE. . Donna's company reimburses her expenses on food, lodging, and conveyance during business trips. The company pays $50 a day for food and lodging and $0.60 for each mile traveled. Donna drove 200 miles and was reimbursed $1620.. . Part A: Create an equation that will determine the number of days x on the trip (3 points). . Part B: Solve this equation justifying each step with an algebraic property of equality. (6 points). . Part C: How many days did Donna spend on this trip? (1 points)

Respuesta :

Well, she drove 200 miles, at a pay of $0.60 per mile travelled. 
200 * 0.6 = 120 
She got payed $120 for her 200 miles traveled. 

Since she gets payed $50 per day, and she got paid $1500 for her food and lodging, she traveled for 30 days as 1500/50 = 30 (Part C answer) 

If you were to determine her total pay: 
Using variables x for: number of days spent on trip 
Y: number of miles traveled. 

Total pay = 50x + 0.6y 
If you'd rather have only the equation for the number of days spent on her trip: 
X = (1620- 0.6(200))/50. (Part A answer) 

Solving for x: 

X = (1620 - 0.6(200))/50 
X = (1620 - 120)/50 
X = (1500)/50 
X = 30 (Part B answer)
Part A. 50*a+ 0.6*200= 1620

Part B.
Using subtraction property in an equation:
50*a + 0.6*200 -0.6*200=1620 - 0.6*200

50*a=1620-0.6*200
Simplifying:
50*a = 1620-120 =1500

Using division property:
50*a/50 = 1500/50
a= 30
 

Part C. 50*a+ 0.6*200= 1620
Simplifying:
a=(1620 - 0.6*200)/50
a= 30 days

Otras preguntas