Answer:
0
2817.43213 N/C
281.74321 N/C
Explanation:
The metal rod is conducting electricity. This means that the charges are being carried on the surface. Inside the rod there is no electric field. So, the electric field intensity is zero at a distance 3.1 cm.
[tex]\epsilon_0[/tex] = Permittivity of free space = [tex]8.85\times 10^{-12}\ F/m[/tex]
r = Distance
[tex]\lambda[/tex] = Charge per unit length = 28.2 nC/m
Electric field is given by
[tex]E=\dfrac{\lambda}{2\pi \epsilon_0r}\\\Rightarrow E=\dfrac{28.2\times 10^{-9}}{2\pi \times 8.85\times 10^{-12}\times 0.18}\\\Rightarrow E=2817.43213\ N/C[/tex]
The electric field intensity is 2817.43213 N/C
[tex]E=\dfrac{\lambda}{2\pi \epsilon_0r}\\\Rightarrow E=\dfrac{28.2\times 10^{-9}}{2\pi \times 8.85\times 10^{-12}\times 1.8}\\\Rightarrow E=281.74321\ N/C[/tex]
The electric field intensity is 281.74321 N/C
