Answer: The difference in the pH values of the two solutions is 2.7
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
[tex]pH=-\log [H^+][/tex]
a) For solution A, let [tex][H^+][/tex] = [tex]0.0001\times 500M=0.05M[/tex]
Putting in the values:
[tex]pH=-\log[0.05][/tex]
[tex]pH=1.3[/tex]
b) For solution B, [tex][H^+][/tex] =[tex]0.0001M[/tex]
Putting in the values:
[tex]pH=-\log[0.0001][/tex]
[tex]pH=4[/tex]
Thus the difference in pH will be (4-1.3)= 2.7.
The difference in the pH values of the two solutions is 2.7
Let the [H+] of solution B be 0.0001 M
Thus,
The [H+] of solution A = 0.0001 × 500 = 0.05 M
For solution A:
Hydrogen ion concentration [H+] = 0.0001 M
pH =?
pH = –Log [H+]
pH = –Log 0.0001
For solution B:
Hydrogen ion concentration [H+] = 0.05 M
pH =?
pH = –Log [H+]
pH = –Log 0.05
pH of solution A = 1.3
pH of solution B = 4
Difference = 4 – 1.3
Therefore, the difference in the pH values of the two solutions is 2.7
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