Answer:
B=9.1397*10^-4 Tesla
Explanation:
To find the velocity first we put kinetic energy og electron is equal to potential energy of electron
K.E=P.E
[tex]\frac{1}{2}*m*v^{2} =e*V[/tex]
where :
m is the mass of electron
v is the velocity
V is the potential difference
[tex]v=\sqrt{\frac{2*e*V}{m} }[/tex] eq 1
Radius of electron moving in magnetic field is given by:
[tex]R=\frac{m*v}{q*B}[/tex] eq 2
where:
m is the mass of electron
v is the velocity
q=e=charge of electron
B is the magnitude of magnetic field
Put v from eq 1 into eq 2
[tex]R=\frac{m*\sqrt{\frac{2*e*V}{m} } }{e B}[/tex]
[tex]B=\sqrt{\frac{2*m*V}{e*R^{2} } }[/tex]
[tex]B=\sqrt{\frac{2*(9.31*10^{-31})*(2.12*10^{3}) }{(1.60*10^{-19})*(0.170)^{2} } }[/tex]
B=9.1397*10^-4 Tesla
