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A worker invested ​$26 comma 000 in two​ accounts, one yielding 5​% interest and the other yielding 8​%. If he received a total of​ $1570 in interest at the end of the​ year, how much did he invest at 5​%?

Respuesta :

Answer:

x = 17000

Explanation:

Given data:

invested amount is $26 000 in 2 accounts

for one account  - interest rate is 5%

for second account interest rate is 8%

total amount received is $1570

assume x is amount in invested in first account

y is amount is invested in second amount

x + y = 26000

we know that total amount recieved is $1570 hence we have

0.05 x + 0.08 y = 1570

solving for x

[tex]x = \frac{1570 - 0.08y}{0.05}[/tex]

putting x value in above equation

[tex]\frac{1570 - 0.08y}{0.05} +  y = 26000[/tex]

multiply eq by 0.05

[tex]1570 - 0.08y + 0.05 y = 26000 \times 0.05[/tex]

1570 - 0.03y = 1300

270 = 0.03 y

y = 9000

hence x = 17000

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