Answer: 60.65 m
Explanation
Use eqation for distance for vertical throw( down)
Vo=12m/s
t=2.5
S=Vot +gt^2/2
S=12*2.5+9.81*2.5^2/2
S=30+30.65
S=60.65m
The displacement is a vector quantity.The height of the given bridge is 60.65 m.
The height of the bridge can calculate by the Projectile motion formula,
[tex]\bold {S = V_ot + \dfrac 12 gt^2}[/tex]
Where,
S - displacement
Vo - initial velocity = 12 m/s
t - time taken = 2.5
g - gravitational acceleration = [tex]\bold { 9.81\ m/s ^2}[/tex]
Put the values in the formula,
[tex]\bold {S = 12\times 2.5+ \dfrac 12 \times 9.81\times 2.5^2}\\\\\bold {S = 30+30.65}\\\\\bold {S = 60.65\ m}[/tex]
Since, the displacement of the stone is ewual to the height of the bridge.
Therefore, the height of the bridge is 60.65 m.
To know more about displacement,
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