A roller coaster engineer is trying to design a new coaster to build at the theme park. The cars, when loaded with people, is expected to have a mass of 8000. He wants his roller coaster cars to be going 10 m/s when it reaches the bottom. Assuming that friction is negligible, how high up should the roller coaster start?

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Then Answer
Well, it turns out that friction is not negligible, the Engineer figured out that the car is going to lose 32000 Joules energy as it goes down the track. this means that he has to start up even higher. what is the actual starting height after taking into account the energy loss from friction?

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Respuesta :

1) The initial height of the roller coaster must be 5.1 m

2) The height of the roller coeaster must be 5.5 m

Explanation:

1)

We can solve this problem by using the law of conservation of energy.

In fact, in absence of frictional force, the total mechanical energy must be conserved, so we can write:

[tex]KE+PE = KE'+PE'[/tex]

where

KE = 0 is the initial kinetic energy, at the top (the car starts from rest, so it has zero speed and so zero kinetic energy)

PE = mgh is the initial potential energy, where

m = 8000 kg is the mass of the car

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

h is the initial height

[tex]KE'=\frac{1}{2}mv'^2[/tex] is the kinetic energy of the car at the bottom, where

v' = 10 m/s is the speed of the car at the bottom

PE' = 0 is the potential energy at the bottom (where h = 0)

Re-writing the equation with all the values and solving for h, we find the initial height of the track:

[tex]h=\frac{v^2}{2g}=\frac{10^2}{2(9.8)}=5.1 m[/tex]

2)

In this case, we also have to take into account the energy lost due to friction. So the equation of conservation of energy becomes

[tex]KE+PE = KE'+PE'+W[/tex]

where

W = 32,000 J is the work done by friction

Re-arranging the equation and solving again for h, we find:

[tex]mgh = \frac{1}{2}mv'^2 + W\\h=\frac{v^2}{2g}+\frac{W}{mg}=5.1+\frac{32,000}{(8000)(9.8)}=5.5 m[/tex]

Learn more about kinetic energy and potential energy:

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