Respuesta :

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0.2577 moles of ions

Explanation:

The dissociation of Rb₂SO₄ in water:

Rb₂SO₄ (s) + H₂O (l) → 2 Rb²⁺ (aq) + SO₄²⁻ (aq)

where:

(s) - solid

(l) - liquid

(aq) - aqueous

(aq) - aqueous

Knowing the dissociation of Rb₂SO₄ in water, we devise the following reasoning:

if         1 mol of Rb₂SO₄ dissociate in 2 moles of Rb²⁺ and 1 mole of SO₄²⁻

then   0.0859 moles of Rb₂SO₄ dissociate in X moles of Rb²⁺ and Y moles of SO₄²⁻

X = (0.0859 × 2) / 1 = 0.1718 moles of Rb²⁺

Y = (0.0859 × 1) / 1 = 0.0859 moles of SO₄²⁻

total moles of ions = moles of Rb²⁺ ions + moles of SO₄²⁻ ions

total moles of ions = 0.1718 + 0.0859 = 0.2577 moles

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Total moles of ions released when 0.0859 mol of Rb2SO4 dissolves completely in water are 0.2577 mol.

What are moles?

In the International System of Units, Mole is the base unit of the amount of any substance.

The dissociation of [tex]Rb_2SO_4[/tex] in water:

[tex]\rm Rb_2SO_4 (s) + H_2O (l) = 2 Rb^2^+ (aq) + SO_4^\;^2^- (aq)[/tex]

If 1 mol of [tex]Rb_2SO_4[/tex] dissociating into 2 moles of Rb²⁺ and 1 mole of SO₄²⁻

Then, 0.0859 mol of [tex]Rb_2SO_4[/tex] will dissociate into?

[tex]X = \dfrac{(0.0859 \times 2) }{1 } = 0.1718 moles\; of\; Rb^2^+[/tex]

[tex]Y= \dfrac{(0.0859 \times 2) }{1 } = 0.0859\; moles\; of\; So_4\;^2^-[/tex]

Total moles of ions  = moles of Rb²⁺ ions + moles of SO₄²⁻ ions

Total moles of ions = 0.1718 + 0.0859 = 0.2577 moles

Thus, the moles of ions are 0.2577 mol.

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