Answer:
Q = 940.5 j
Explanation:
Given data:
Mass of iron = 95 .00 g
Initial temperature = 36.0°C
Final temperature = 58°C
Heat lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of iron = 0.450 j/g.°C
ΔT = T2-T1
ΔT = 58°C-36.0°C
ΔT = 22°C
Q = m.c. ΔT
Q = 95.00 g × 0.450 j/g.°C × 22°C
Q = 940.5 j
