Respuesta :
area of a cirlce=πr²
we have two radius:2r and r
area of the cirlce₁ + area of the circle₂=80 m²
area of the circle₁=π(2r)²
area of the circle₂=πr²
Then, we can suggest this quation:
π(2r)²+πr²=80
4πr²+πr²=80
π(4r²+r²)=80
π(5r²)=80
5πr²=80
r²=80/5π
r=√(80/5π)≈2.26
radius of the largest cirlce=2r=2(2.26)=4.51
Answer: the radius of the largest circle is 4.51 m
we have two radius:2r and r
area of the cirlce₁ + area of the circle₂=80 m²
area of the circle₁=π(2r)²
area of the circle₂=πr²
Then, we can suggest this quation:
π(2r)²+πr²=80
4πr²+πr²=80
π(4r²+r²)=80
π(5r²)=80
5πr²=80
r²=80/5π
r=√(80/5π)≈2.26
radius of the largest cirlce=2r=2(2.26)=4.51
Answer: the radius of the largest circle is 4.51 m
A1 + A2 = 80 ,,, R1= 2R2
pi* R1^2 + pi * R2^2 = 80
R1^2 + R2^2 = 80/pi
sub. by R1 = 2R2
(2R2)^2 + R2^2 = 80/pi
5R2^2 = 80/pi
R2^2 = 16/pi
R2 = 2.256 m
R1 = 2 R2
So,, R1 = 4.513 m
pi* R1^2 + pi * R2^2 = 80
R1^2 + R2^2 = 80/pi
sub. by R1 = 2R2
(2R2)^2 + R2^2 = 80/pi
5R2^2 = 80/pi
R2^2 = 16/pi
R2 = 2.256 m
R1 = 2 R2
So,, R1 = 4.513 m