Answer:
(3x^2 − 1)(3x^2 + 1)(9x^4 + 1) or C
Step-by-step explanation:
First let's use the identity for the difference of 2 squares
a^2 - b^2 = (a - b)(a + b)
Next we have to put a^2 = 81x^8 and b^2 = 1 giving a = 9x^4 and b = 1 to factor, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Finally after applying the difference of 2 squares to 9x^4 - 1:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Thus being the answer.
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