Answer:
The radiation pressure on the mirror is [tex]5.7\times10^{-5}\ N/m^2[/tex].
Explanation:
Given that,
Power = 25.8 mW
Diameter = 1.96 mm
We need to calculate the force
Using formula of power
[tex]P=Fc[/tex]
Where, P = power
F = force
c = light of speed
Put the value into the formula
[tex]25.8 \times10^{-3}=F\times3\times10^{8}[/tex]
[tex]F=\dfrac{25.8 \times10^{-3}}{3\times10^{8}}[/tex]
[tex]F=8.6\times10^{-11}[/tex]
We need to calculate the radiation pressure on the mirror
Using formula of radiation pressure
[tex]P=\dfrac{2F}{A}[/tex]
Put the value into the formula
[tex]P=\dfrac{2\times8.6\times10^{-11}}{\pi\times(0.98\times10^{-3})^2}[/tex]
[tex]P=5.7\times10^{-5}\ N/m^2[/tex]
Hence, The radiation pressure on the mirror is [tex]5.7\times10^{-5}\ N/m^2[/tex].
