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What is the slope-intercept form of the equation of a line that passes through (1, –6) with a slope of 5?
a)

y = 5x + 11


b)

y = 5x + 1


c)

y = 5x – 11


d)

y = 5x – 6

Respuesta :

absor201

Answer:

c) y = 5x – 11

Step-by-step explanation:

The standard form of point-slope equation of line is:

y = mx+b

We know that

m = 5

Putting the value of m

y = 5x +b

To find the value of b, put the point in the equation

-6 = (5)(1)+b

-6 = 5+b

-6-5 = b

b = -11

Putting the values of b and m in standard form

y = 5x-11

Hence, option c: y = 5x – 11  is the correct answer ..

luisejr77

Answer: option c.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

[tex]y=mx+b[/tex]

Where "m" is the slope and "b" is the y-intercept.

In this case we know that the slope of the line is:

[tex]m=5[/tex]

Knowing that it passes through the point (1, -6), we can substitute the coordinates into [tex]y=mx+b[/tex] and solve for "b":

[tex]-6=5(1)+b\\\\-6-5=b\\\\b=-11[/tex]

Therefore, substituing values, we get that the equation of this line in Slope-Intercept form is:

[tex]y=5x-11[/tex]

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