Answer:
[tex]-\frac{31}{8}[/tex]
Step-by-step explanation:
We are given that an expression
[tex](\frac{1}{2})^2-6(2-\frac{2}{3})[/tex]
We have to find the value as a simplified fraction
[tex]\frac{1}{2}\times \frac{1}{2}-6(\frac{6-2}{3})[/tex]
[tex]\frac{1}{4}-6\times\frac{4}{3}[/tex]
[tex]\frac{1}{4}-2\times 4[/tex]
[tex]\frac{1}{4}-8[/tex]
[tex]\frac{1-32}{8}[/tex]
[tex]-\frac{31}{8}[/tex]
Hence, [tex](\frac{1}{2})^2-6(2-\frac{2}{3})=-\frac{31}{8}[/tex]
