Respuesta :
Answer:
99.67 cm to the left of second lens
Explanation:
For the first lens :
[tex]d_{o}[/tex] = Distance of the object = 18 cm
[tex]f[/tex] = focal length of the lens = 9 cm
[tex]d_{i}[/tex] = Distance of the image
Using the lens equation
[tex]\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}[/tex]
[tex]\frac{1}{18} + \frac{1}{d_{i}} = \frac{1}{9}[/tex]
[tex]d_{i} = 18 [/tex] cm
[tex]d[/tex] = distance between the two lenses = 29.5 cm
For the second lens, the image formed by the first lens acts as the object
For the second lens :
[tex]d_{o}[/tex] = Distance of the object = [tex]d - 18[/tex] = [tex]29.5 - 18[/tex] = [tex]11.5[/tex] cm
[tex]d_{i}[/tex] = Distance of the image
[tex]f[/tex] = focal length of the lens = 13 cm
Using the lens equation
[tex]\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}[/tex]
[tex]\frac{1}{11.5} + \frac{1}{d_{i}} = \frac{1}{13}[/tex]
[tex]d_{i} = - 99.67 [/tex] cm
The image is located 99.67 cm to the left of the second lens
