contestada

Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. The radius of the snow cone is 6 inches, and the height of the cone is 10 inches. If the diameter of the bubble gum is 1.5 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice?

1 over 3(3.14)(102)(6) − 4 over 3(3.14)(1.53)
1 over 3(3.14)(62)(10) − 4 over 3(3.14)(1.53)
1 over 3(3.14)(102)(6) − 4 over 3(3.14)(0.753)
1 over 3(3.14)(62)(10) − 4 over 3(3.14)(0.753)

Respuesta :

wegnerkolmp2741o

Answer:

V = 1/3 pi (6)^2 *10 - 4/3 pi (.75)^3

Step-by-step explanation:

Find the volume of the cone without the bubble gum

The radius is 6 inches and the height is 10

V =1/3 pi r^2 h

V = 1/3 pi (6)^2 *10

Now find the volume of the sphere with the bubble gum

The diameter is 1.5 inches

That means the radius is 1.5/2 = .75

V =4/3 pi r^3 h

V = 4/3 pi (.75)^3

Take the volume of the cone and subtract the volume of the bubble gum

V = 1/3 pi (6)^2 *10 - 4/3 pi (.75)^3

The equation i.e. used for determining the volume of the cone is [tex]V = 1/3 \pi (6)^2 \times 10 - 4/3 \pi (.75)^3[/tex]

Calculation of the equation used:

The radius is 6 inches and the height is 10

Now

[tex]V =1/3 \pi r^2 h\\\\V = 1/3 \pi (6)^2 \times 10[/tex]

Now find the volume of the sphere with the bubble gum

Since The diameter is 1.5 inches

That means the radius is 1.5/2 = .75

So,

[tex]V =4\div 3 \pi r^3 h\\\\V = 4\div 3 \pi (.75)^3[/tex]

Here we considered that

Take the volume of the cone and subtract the volume of the bubble gum

So,

[tex]V = 1/3 \pi (6)^2 \times 10 - 4/3 \pi (.75)^3[/tex]

Learn more about the volume here: https://brainly.com/question/22474603