Answer:a-0
b-2 m
Explanation:
Given mass of the body is 2 kg
Force acting on the body =-6x N
Velocity at x=3m is 8m/s
Now acceleration of the body is -3x
a=-3x
[tex]\frac{vdv}{dx}[/tex]=-3x
vdv=-3xdx
integrating both sides we get
[tex]\int vdv=\int -3xdx[/tex]
[tex]\frac{v^2}{2}[/tex]=[tex]\frac{x^2}{2}[/tex]+c
Now at x=3m v=8m/s
substituting values
c=[tex]\frac{37}{2}[/tex]
Thus [tex]v^2=-3x^2+37[/tex]
Velocity will be zero after [tex]x=\sqrt{\frac{37}{3}}[/tex]
thus velocity of the body is zero at x=4 m
[tex]\left ( b\right )[/tex]
v=5m/s
25=-3x^2+37
x=2 m