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Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a+3.75b=2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?]

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TaeKwonDoIsDead

Answer:

168

Step-by-step explanation:

The first equation given as  [tex]10.50a+3.75b=2071.50[/tex]

Where a is the number of adults and b is the number of students

Since, the number of students are given as 82, we can plug 82 into b and then do algebra and solve for a (shown below):

[tex]10.50a+3.75b=2071.50\\10.50a+3.75(82)=2071.50\\10.50a+307.5=2071.50\\10.50a=2071.50-307.5\\10.50a=1764\\a=\frac{1764}{10.50}\\a=168[/tex]

Thus, 168 adult tickets were sold

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