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PLEASE HELP! A zoo feeds it’s monkeys a mixture of fruits and vegetables. The ratio of fruits and vegetable is shown in the diagram.

PLEASE HELP A zoo feeds its monkeys a mixture of fruits and vegetables The ratio of fruits and vegetable is shown in the diagram class=

Respuesta :

calculista

Answer:

Part 1) Monkey A [tex]42\ vegetables[/tex]

Part 2) Monkey B [tex]50\ fruits[/tex]

Step-by-step explanation:

Let

x -----> the number of fruits

y ----> the number of vegetables

we know that

The ratio of fruits  and vegetables is equal to

[tex]\frac{x}{y} =\frac{5}{7}[/tex]

Part 1) Find the number of vegetables Monkey A

we know that

[tex]\frac{x}{y} =\frac{5}{7}[/tex]

[tex]x=30\ fruits[/tex]

substitute and solve for y

[tex]\frac{30}{y} =\frac{5}{7}[/tex]

[tex]y=30*7/5=42\ vegetables[/tex]

Part 2) Find the number of fruits Monkey B

we know that

[tex]\frac{x}{y} =\frac{5}{7}[/tex]

[tex]y=70\ vegetables[/tex]

substitute and solve for x

[tex]\frac{x}{70} =\frac{5}{7}[/tex]

[tex]x=70*5/7=50\ fruits[/tex]

JeanaShupp

Answer with explanation:

From the given picture , it can be seen that the ratio of the fruits to the vegetables is 5:7

Let x be the number of vegetables corresponds 30 fruits for Monkey A.

Then , by using proportional relationships between fruits and vegetables , we have :-

[tex]\dfrac{x}{30}=\dfrac{7}{5}\\\\\Rightarrow\ x=\dfrac{30\times7}{5}=42[/tex]

So, the number of vegetables for Monkey A = 42

Let y  be the number of vegetables corresponds 70 vegetables for Monkey B.

Then , we have :-

[tex]\dfrac{y}{70}=\dfrac{5}{7}\\\\\Rightarrow\ x=\dfrac{70\times5}{7}=50[/tex]

So, the number of fruits for Monkey B = 50

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