Respuesta :
Answer:
b
Step-by-step explanation:
Given
[tex]\frac{x^2-2x-3}{4x^2-12}[/tex]
Substitute x = 3 into the expression
= [tex]\frac{3^2-2(3)-3}{4(3)^2-12}[/tex]
= [tex]\frac{9-6-3}{36-12}[/tex]
= [tex]\frac{0}{24}[/tex] = 0 → b
Answer:
b
Step-by-step explanation:
Given
[tex]\frac{x^2-2x-3}{4x^2-12}[/tex]
Substitute x = 3 into the expression
= [tex]\frac{3^2-2(3)-3}{4(3)^2-12}[/tex]
= [tex]\frac{9-6-3}{36-12}[/tex]
= [tex]\frac{0}{24}[/tex] = 0 → b