Respuesta :

Answer:

see explanation

Step-by-step explanation:

Find equivalent routes for the directed lines, that is

(a)

FE = FA + AB + BE = b + a - 3b = a - 2b

(b)

BC = BE + ED + DC = - 3b + a + 2b = a - b

(c)

FC = FA + AB + BE + ED + DC

     = b + a - 3b + a + 2b = 2a