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The voltage in a lightbulb is given by the equation V= IR. In this equation, Vis
the voltage, lis the current, and Ris the resistance. What is the current in a
lightbulb with a voltage of 35.0 V and a resistance of 175 n?
O A. 6125 A
O B. 1.40 A
O C. 0.200 A
O D. 5.00 a

Respuesta :

meghanbf

V=IR

35=I(175)

*Divide both sides by 175*

0.2=I

C. 0.200 A

Hope this helps!!

The current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohm is 0.2 A.

Find the current in a lightbulb?

Given:

  • The voltage in a lightbulb is given by the equation V=IR
  • V is the voltage, I is current, and R is the resistance.
  • The voltage of the lightbulb is given as 35.0 V.
  • The resistance of the lightbulb is given as 175 Ohm.

As the equation is given,

V= IR

where I is current, R is resistance and V is the voltage.

Now, I = V/R

As the value of Voltage and resistance of the lightbulb is given, we will put in the above equation, we get;

I = 35.0/ 175 A

I = 0.2 A.

Hence, the current of the lightbulb is 0.2 A.

Therefore, Option C is the correct answer.

To learn more about Current, refer to:

https://brainly.com/question/13562393

#SPJ2

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