contestada

The range is the horizontal distance from the cannon when the pumpkin hits the ground. This distance is given by the product of the horizontal velocity (which is constant) and the amount of time the pumpkin is in the air (which is determined by the vertical component of the initial velocity, as you just discovered). Set the initial speed to 14 m/s, and fire the pumpkin several times while varying the angle between the cannon and the horizontal. For which angle is the range a maximum (with the initial speed held constant)?

Angle:
0
60
45
90
30

Respuesta :

AL2006

The answer is 45 degrees.  I am not doing a field experiment for you that involves a cannon and a day's work, for 5 points.

For 45° angle, the range of the pumpkin is maximum with constant initial velocity.

To find the answer, we need to know about the mathematical expression of range in terms of initial velocity and projectile angle.

What is the time of flight of pumpkin in the air?

  • From Newton's equation of motion, we know the time of flight is 2usinФ/g.
  • Where u is the initial velocity and Ф is the angle of projection.

What is the mathematical formulation of range of the pumpkin?

  • Range is given as flight time × horizontal velocity.
  • So, range = (2usinФ/g)×ucosФ

                         = usin2Ф/g

Thus, we can conclude that the range will be maximum when the angle is 45° with constant initial velocity.

Learn more about the range of projectile here:

brainly.com/question/15502195

#SPJ2

Otras preguntas