Answer:
[tex]\boxed{\rm 3Ca^{2+} + 2PO_{4}^{3-} \longrightarrow Ca_{3}(PO_{4})_{2}}[/tex]
Explanation:
[tex]\textbf{Ionic equation}\\\rm \textbf{6Na}^{+} + 3Ca^{2+} + \textbf{6Cl}^{-} + 2PO_{4}^{3-} \longrightarrow \textbf{6Na}^{+} + \textbf{6Cl}^{-} + Ca_{3}(PO_{4})_{2}[/tex]
Net ionic equation
Cancel all ions that appear on both sides of the reaction arrow (in boldface).
[tex]\boxed{\rm 3Ca^{2+} + 2PO_{4}^{3-} \longrightarrow Ca_{3}(PO_{4})_{2}}[/tex]
Answer:
B) 2PO3/4- + 3Ca^2+ ----> Ca3(PO4)2
Explanation:
Correct on edge
