Answer:
domain; x<0 or x>0
Step-by-step explanation:
We have been given the following function;
f(x) = 2x + 6/x^2 + 5x + 6
We need to evaluate the values of f(x) for the following domain values;
{-3, -2, 0, 2, 3}
f(-3) = 2(-3) + 6/(-3)^2 + 5(-3) + 6
= -43/3
f(-2) = 2(-2) + 6/(-2)^2 + 5(-2) + 6
= -6.5
f(0) = 2(0) + 6/(0)^2 + 5(0) + 6
= undefined
f(2) = 2(2) + 6/(2)^2 + 5(2) + 6
= 21.5
f(3) = 2(3) + 6/(3)^2 + 5(3) + 6
= 83/3
The function is real and defined for every value of x in its domain except where x = 0 . This is a point of discontinuity.
Find the attachment below;
