A cube has edge length 6 in. If the edge length of the cube is doubled, what happens to the surface area?

In the given question,
The edge length of the cube is 6 inches
Therefore, the surface area is;
[tex]6a^{2}=6\times6^{2}\\=6\times36\\=216 in^{2}[/tex]
If the edge length of the cube is doubled,
Then, the new edge length is 6*2=12inches
Therefore, the new surface area is;
[tex]6a^{2}=6\times12^{2}\\=6\times144\\=864 in^{2}[/tex]
Therefore, the change in the surface area is,
864/216 = 4
That is, the new surface area is four times of the old surface area.
Hence, option (B) is correct.
Learn more about surface area at https://brainly.com/question/16519513
#SPJ2