To find the intercepts, the other number will be 0 (x-intercept: when y is 0, and vise-versa).
So:
x-intercept: 0 + 1 = 3x - 12 -> 3x = 13 -> x = 13/3, so it will be ([tex]\frac{13}{3}[/tex], 0).
y-intercept: y + 1 = 3*0 - 12 -> y = -13, so it will be (0, -13).
Answer:
x-intercept = [tex]\frac{13}{3}[/tex]
y-intercept = [tex]-13[/tex]
Step-by-step explanation:
We are given the following equation of a line and we are to find the x and y intercepts for it:
[tex] y + 1 = 3 ( x - 4 ) [/tex]
To find the x-intercept, we will put in 0 for the y to get:
[tex] 0 + 1 = 3 ( x - 4 ) \\\\ 1 = 3 x - 12 \\\\ 3 x = 1 + 12 \\\\ x = \frac { 13 } { 3 } [/tex]
To find the y-intercept, we will put in 0 for the x to get:
[tex] y + 1 = 3 ( 0 - 4 ) \\\\ y + 1 = -124 \\\\ y = - 12 - 1 \\\\ y = - 13 [/tex]
So the x-intercept is [tex]\frac{13}{3}[/tex] while the y-intercept is [tex]-13[/tex].
