Answer:
[tex]\Rightarrow \dfrac{576}{625}[/tex]
Step-by-step explanation:
Given:
Expression, [tex](3x^3y^{-2})^2[/tex]
To find the value of expression at x=-3 and y=5
Put the values into expression
[tex]\Rightarrow (3(-2)^3(5)^{-2})^2[/tex]
[tex]\Rightarrow (3\cdot -8\cdot \dfrac{1}{25})^2[/tex] [tex]\because x^{-m}=\dfrac{1}{x^m}[/tex]
[tex]\Rightarrow (-\dfrac{24}{25})^2[/tex]
[tex]\Rightarrow \dfrac{576}{625}[/tex]
Hence, The value of expression would be [tex]\Rightarrow \dfrac{576}{625}[/tex]
