The perimeter of rectangle ABCD is 256 inches. Its length is 3 times as long as its width. Find the area of triangle ABC.

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gmany

Answer:

[tex]\large\boxed{A_\triangle==1,536\ in^2}[/tex]

Step-by-step explanation:

The formula of a perimeter of a rectangle:

[tex]P=2(l+w)[/tex]

The formula of an area of a rectangle:

[tex]A=lw[/tex]

l - lenght

w - width

We have l = 3w and the perimeter P = 256 in. Substitute:

[tex]2(3w+w)=256[/tex]               divide both sides by 2

[tex]4w=128[/tex]               divide both sides by 4

[tex]w=32\ in\to l=3(32)=96\ in[/tex]

Calculate the area of a rectangle:

[tex]A=(96)(32)=3,072\ in^2[/tex]

The triangle ABC is the half of the rectangle. Therefore the area of a triangle ABC is:

[tex]A_\triangle=\dfrac{3,072}{2}=1,536\ in^2[/tex]