Answer:
x= [tex]\frac{1}{6}[/tex]
Step-by-step explanation:
We have given,
[tex]\sqrt{3-5x} =\sqrt{x+2}[/tex]
We need to solve for x.
[tex]\sqrt{3-5x} =\sqrt{x+2}[/tex]
Squaring both sides, we get:
3-5x = x + 2
or 3 - 2 = x + 5x
or 1 = 6x
or x = [tex]\frac{1}{6}[/tex]
Hence we got x= [tex]\frac{1}{6}[/tex]