Respuesta :
Fluorine (F) has higher potential energy as Neon (N) is a noble/inert gas.
Fluorine will lose another electron to gain stability.
Fluorine has the higher potential energy. And the statement, "This atom will lose two more electrons to fill its outer energy level" is correct.
The concept of potential energy of an atoms is like that, the electrons absorb energy, they excites and move to higher energy level. Then the distance between lower energy level and higher energy level decides the potential energy. Which means, higher the energy level, higher will be the potential energy.
Also, more the tendency to loose electrons, more will be the potential energy of electrons of an atoms.
- In the given problem, the neon (Ne) is a noble gas which do not has tendency to either loose electrons or gain electrons. Which means it is highly stable and do not have any observed value of potential energy.
- While fluorine has the electronic configuration of [tex][2s^{2}\;\; 2p^{5}][/tex], which means it has the tendency to loose two electrons to gain the stability. So, compared to neon, fluorine has higher potential energy. Because the atoms will loose two more electrons to fill its outer energy level.
Thus, we can conclude that fluorine has the higher potential energy. And the statement, "This atom will lose two more electrons to fill its outer energy level" is correct.
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