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Solve for x.


−3x + 4b > 9


1.) x > The quantity 4 times b minus 9 all over 3 <-- My answer

2.) x < the quantity 9 minus 4 times b all over 3

3.) x < the quantity negative 4 times b plus 9 all over negative 3

4.) x > the quantity 4 times b plus 9 all over negative 3

Respuesta :

tramserran

Answer: [tex]\bold{x < \dfrac{4b-9}{3}}[/tex]

Step-by-step explanation:

-3x + 4b > 9

       -4b  -4b  

-3x        > -4b + 9

÷-3       ↓    ÷-3    

  x         [tex]<\dfrac{-4b+9}{-3}[/tex]

  x         [tex]<\dfrac{-1(4b-9)}{-1(3)}[/tex]

  x         [tex]<\dfrac{4b-9}{3}[/tex]

Answer:

A

Step-by-step explanation:

A

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