Let f(x) = 2(3)^(x+1) +4.
The graph of f(x) is stretched vertically by a factor of 2 to form the graph of g(x) .

What is the equation of g(x)?

Enter your answer in the box.

g(x) = ?

Respuesta :

Answer:

[tex]g(x)=4(3)^{\left(x+1\right)}+8[/tex]

Step-by-step explanation:

Given equation is:

[tex]f(x)=2(3)^{\left(x+1\right)}+4[/tex]

Now it says that graph of f(x) is stretched vertically by a factor of 2 to form the graph of g(x).

Now we need to find about what is the equation of g(x).

We know that if function f(x) is stretched vertically by a factor of "a" then we get a*f(x)

Here factor is 2

So we just need to multiply g(x) with 2.


g(x)=a*f(x)

g(x)=2*f(x)

[tex]g(x)=2\left(2(3)^{\left(x+1\right)}+4\right)[/tex]

[tex]g(x)=4(3)^{\left(x+1\right)}+8[/tex]


Hence final answer is:

[tex]g(x)=4(3)^{\left(x+1\right)}+8[/tex]


Answer:

The equation of g(x) is:

[tex]g(x)=4\times 3^{x+1}+8[/tex]

Step-by-step explanation:

We are given a function f(x) as:

[tex]f(x)=2\times 3^{x+1}+4[/tex]

now we are given a condition that the graph of f(x) is stretched vertically by a factor of 2 to form the graph of g(x).

Now we know that for any initial function f(x) if the function is stretched vertically by a factor "a" to form the other function g(x) then the equation of the resultant function is given by:

[tex]g(x)=a f(x)[/tex]

now here [tex]a=2[/tex]

and [tex]f(x)=2\times 3^{x+1}+4[/tex]

Hence, the resultant function g(x) is given by:

[tex]g(x)=2\times (2\times 3^{x+1}+4)[/tex]

[tex]g(x)=4\times 3^{x+1}+8[/tex]

Hence, the equation of g(x) is:

[tex]g(x)=4\times 3^{x+1}+8[/tex].