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If 34.7 g of AgNO₃ react with 28.6 g of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ could be formed? AgNO₃(aq) + H₂SO₄ (aq) → Ag₂SO₄ (s) + HNO₃ (aq)

Respuesta :

kenmyna

The  number  of grams   of Ag2SO4  that could be formed  is   31.8  grams



    calculation

Balanced   equation is  as below

2 AgNO3 (aq)  + H2SO4(aq)  →  Ag2SO4 (s)   +2 HNO3 (aq)


  • Find  the  moles  of  each reactant by use  of  mole= mass/molar mass  formula

that is  moles of  AgNO3= 34.7 g / 169.87  g/mol= 0.204 moles

             moles of  H2SO4 =  28.6  g/98  g/mol  =0.292  moles

  • use the  mole  ratio to determine the moles of  Ag2SO4

   that is;

  •    the mole ratio of  AgNo3 : Ag2SO4 is  2:1 therefore  the  moles of Ag2SO4=  0.204  x1/2=0.102 moles

  • The moles  ratio of H2SO4  : Ag2SO4  is  1:1  therefore  the moles of Ag2SO4 = 0.292  moles

 

  •      AgNO3  is the limiting reagent therefore  the moles of   Ag2SO4 = 0.102  moles

    finally  find  the mass  of Ag2SO4  by use of    mass=mole  x molar mass  formula

that  is  0.102   moles  x  311.8  g/mol= 31.8 grams

The mass of Ag₂SO₄  formed in the reaction of  AgNO₃(aq) + H₂SO₄ (aq) → Ag₂SO₄ (s) + HNO₃ (aq) is 31. 84 g.

Let's write out the unbalance equation and then balance it to solve for the mass of Ag₂SO₄ produced. Therefore,

  • AgNO₃(aq) + H₂SO₄ (aq) → Ag₂SO₄ (s) + HNO₃ (aq)

Balanced equation will be

  • 2AgNO₃(aq) + H₂SO₄ (aq) → Ag₂SO₄ (s) + 2HNO₃ (aq)

mass of AgNO₃  = 34.7 g

molar mass of AgNO₃ = 169.87 g/mol

number of moles of AgNO₃ = 34.7 / 169. 87 = 0.20427385647 moles

mass of H₂SO₄ =  28.6 g

molar mass of H₂SO₄ = 98.079 g/mol

number of moles of H₂SO₄  = 28.6 / 98. 079 = 0.29160166804 moles

2 moles of AgNO₃ reacts with 1 mole of  H₂SO₄ to produce 1 mole of Ag₂SO₄ .

Therefore,

AgNO₃ is the limiting reagent .

Then,

2(169.87 ) of AgNO₃ produces  311.799 g of Ag₂SO₄

34.7 g of AgNO₃ will produce ? of  Ag₂SO₄

cross multiply

mass of  Ag₂SO₄  produce = (311.799 × 34.7)/339.74

mass of  Ag₂SO₄  produce = 10818.7313 / 339.73

mass of  Ag₂SO₄  produce = 31.8441493495

mass of  Ag₂SO₄  produce ≈ 31.84 g

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