What is the slope of segment BC?

Answer:
-4/3
Step-by-step explanation:
slope = (y2 - y1)/(x2 - x1) = (-6 - 2)/(11 - 5) = -8/6 = -4/3
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have B(5, 2) and C(11, -6). Substitute:
[tex]m=\dfrac{-6-2}{11-5}=\dfrac{-8}{6}=-\dfrac{8:2}{6:2}=-\dfrac{4}{3}[/tex]