Consider the reaction cl2(g) + i2(g) <=> 2 icl(g), which is endothermic as written. what would be the effect on the equilibrium position of removing cl2(g)? 1. reaction would go to the left, making more "reactants" 2. no change on the equilibrium position 3. reaction would go to the right, making more "reactants" 4. reaction would go to the left, making more "products" 5. reaction would go to the right, making more "products"

Respuesta :

The given equilibrium reaction is,

[tex]Cl_{2}(g)+I_{2}(g)+Heat<==>2ICl(g)[/tex]

According to Le Chatelier's principle states that when a system in equilibrium is disturbed by varying conditions like concentration, pressure, and temperature of the system, the system tries to counter act the affect by shifting the equilibrium towards the required side.

When [tex]Cl_{2}[/tex] is removed from the system, the concentration of chlorine ([tex]Cl_{2}[/tex]) decreases, the equilibrium is disturbed. So, the system tries to re-establish the equilibrium by moving in that direction which produces more of chlorine, that is towards the reactant side.

The correct answer would be: 1. reaction would go to the left, making more "reactants"

The system that absorbs or requires heat for the reaction is called endothermic. The reaction would go to the left, making more reactants when [tex]\rm Cl_{2}[/tex] is removed.

What happens when the reactant is removed?

The reactant in the reaction is the compound or the substance that undergoes chemical changes to yield products.

The equilibrium would shift to the left and more reactants will be made. The reaction can be shown as,

[tex]\rm Cl_{2}(g) + I_{2}(g) + heat \Leftrightarrow 2ICl(g)[/tex]

According to the principle when a system or the reaction experiences any stress then the system works in the direction to equate or remove the stress. In the reaction removal of the chlorine is the stress.

So the system will respond by making more chlorine in response to its removal from the system and hence the reaction will shift towards the left where the reactants are present.

Therefore, option 1. reaction will shift towards the left making more reactants.

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