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1. A hotel is in the shape of a​ cylinder, with a circular foundation. The circumference of the foundation is 2 times the​ radius, increased by 235.4 ft. Find the radius of the circular foundation. Use 3.14 as an approximation for π.

2. the​ circumference, C, of a circle is given. 28pi ft. Find the values of r​ (radius), d​ (diameter), and A​ (area) for this particular circle. Leave

pi π in your answers.

Respuesta :

2)The circumference or perimeter of a circle with radius [tex] r [/tex] is

[tex] P=2\pi r [/tex]. Given [tex] P=28\pi [/tex]. Therefore,

[tex] 2\pi r =28\pi \\
r=14\\
d=2r=28\\
A=\pi r^2 \\
A=\pi (14)^2\\
A=[tex] 196\pi [/tex]

Thus the radius is [tex] 14\;ft [/tex], diameter [tex] 28\;ft [/tex] and area [tex] 196\pi \;ft^2[/tex]

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