cristy260381
contestada

The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB)=10log[1/10], where I &/ the intensity of a given sound and I0 is the threshold of a hearing intensity. What is the intensity, in decibles, [I(dB)], when I=10^8(I0)? Round to the nearest whole number. (Refer to photo for equations) A.8 B.9 C.19 D.80

Respuesta :

carlosego
For this case we have the following equation:
 [tex]I(dB)= 10log(\frac{I}{I0}) [/tex]
 Where,
 I: the intensity of a given sound
 I0:  the threshold of a hearing intensity
 Substituting values in the given equation we have:
 [tex]I(dB)= 10log(\frac{10^8I0}{I0}) [/tex]
 Rewriting the equation we have:
 [tex]I(dB)= 10log(10^8) [/tex]
 Then, by properties of logarithm we have:
 [tex]I(dB)= 10(8) [/tex]
 Finally we have:
 [tex]I(dB)=80 [/tex]
 Answer:
 The intensity, in decibles, [I(dB)], when I=10^8(I0) is:
 D.80

The intensity, in decibels, [I(dB)], when [tex]\rm I = 10^8I_0[/tex] is 80 and this can be determined by using the given data.

Given :

The intensity or loudness of a sound can be measured in decibels (dB), according to the equation I(dB)=10log[I/[tex]\rm I_0[/tex]], where 'I' is the intensity of a given sound and [tex]\rm I_0[/tex] is the threshold of a hearing intensity.

According to the given data, the intensity or loudness of a sound can be measured in decibels (dB) which is given by:

[tex]\rm I(dB) = 10log\dfrac{I}{I_0}[/tex]

Now, at [tex]\rm I = 10^8I_0[/tex] the intensity is given by:

[tex]\rm I(dB) = 10log\dfrac{10^8\times I_0}{I_0}[/tex]

Simplify the above expression in order to determine the value of I(dB).

[tex]\rm I(dB) = 10log10^8[/tex]

I(dB) = 80 log 10

I(dB) = 80

Therefore, the correct option is D).

For more information, refer to the link given below:

https://brainly.com/question/17323212

Otras preguntas