Respuesta :
Answer:
Center = (2,5)
Radius = 10
Choice A
To find this answer, first write the equation
(x-2)^2 + (y-5)^2 = 100
into
(x-2)^2 + (y-5)^2 = 10^2
Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
We see that (h,k) = (2,5) is the center
and r = 10 is the radius
Center = (2,5)
Radius = 10
Choice A
To find this answer, first write the equation
(x-2)^2 + (y-5)^2 = 100
into
(x-2)^2 + (y-5)^2 = 10^2
Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
We see that (h,k) = (2,5) is the center
and r = 10 is the radius
Answer:
A) Center ( 2 , 5 ) ; radius = 10 .
Step-by-step explanation:
Given : (x - 2)² + (y - 5)² = 100.
To find : What is the center and radius of the circle with equation.
Solution : We have given (x - 2)² + (y - 5)² = 100.
Standard form of circle : (x - h)² + (y - k)² = r².
Where, center = ( h ,k ) , r = radius .
On comparing (x - 2)² + (y - 5)² = 100 with (x - h)² + (y - k)² = r².
We can write (x - 2)² + (y - 5)² = 10².
h = 2 , k = 5 , r = 10 .
Center ( 2 , 5 ) ; radius = 10 .
Therefore, A) Center ( 2 , 5 ) ; radius = 10 .
