Respuesta :

Willchemistry
Molar mass of LiBr ( lithium bromide ) =  86.845 g/mol

Amount of calculation to moles of lithium bromide (LiBr)

86.845 g ------------- 1 mole
100 g ----------------- ?

n = m / M

n = 100 / 86.845

n = 1.1514 moles of LiBr

 V  ---------------------1.1514 moles
1 L  --------------------  4 M

1.1514 * 1 / 4

V = 1151.4 / 4

V = 0,28785 L

hope this helps!

hope this helps !

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